Question

find the position nature in the size of object 5 cm high placed at a distance of 15 cm from a concave mirror of focal length 30 cm

Answer 1

ho = 5 cm, u = - 15 cm, f = 30 cm

1/f = 1/v + 1/u

1/v = 1/f - 1/u = 1/30 + 1/15 = 1/10

v = 10 cm

m = hi / ho = v / u

hi = (v / u) * ho = - (10 / -15) * 5 = 3.33 cm

nature: virtual and erect and diminished.

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