find the position , nuture and size of the image formed by a convex lens of focal length 12 cm of an object 5 cm high placed at a distance 20 cm from it
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Position of the image-beyond 2f(centre of curvature).
Nature of image-real and inverted.
Size of image,
-1/v-1/u=1/f
-1/v-1/20=-1/12
-1/v=1/20-1/12
-1/v=(3-5)/60
-1/v=-2/60=-1/30
v=30
So magnification=30/20=3/2
So image size=5×3/2=15/2=7.5 cm.
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