Question

Find the position of 62 in following series 2,5,8?
(A) 26
(B) 21
(C) 20
D. 23

Answer 1

D=5-2=3

A=2

AN=62

AN=a+(n-1)d

62=2+(n-1)3

62-2=(n-1)3

60\3=(n-1)

20=(n-1)

20+1=n

21=n

SO THE 21 TH POSITION .

THE RIGHT ANSWER IS (B)

hope it helps

Answer 2

Given : The series is 2,5,8...

To find : The position of 62 in the given series.

Solution :

We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the position of 62 in the given series)

Now,

Common difference between two consecutive terms :

• Second term - First term = 5-2 = 3
• Third term - Second term = 8-5 = 3

There is equal common difference between two consecutive terms. That's why this will be considered as an AP series.

Let, 62 be nth term of the AP series.

First term of the AP (a) = 2

Common difference (d) = 3

So,

nth term of the AP = a + (n-1) × d = 2 + (n-1) × 3 = 2 + 3n -3 = 3n - 1

Comparing the two values of nth terms of the AP series, we get :

3n - 1 = 62

3n = 62 + 1

3n = 63

n = 63/3

n = 21

So, 62 is 21st term.

(This will be considered as the final result.)

Hence, 62 is 21st term of the series.