find the position of an object held in front concave lens of focal length 12cm so as to form a real image and 4 times magnified.
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Answered by
0
Answer:
ANSWER
v
1
−
u
1
=
12
1
uv
u−v
=
12
1
-(1)
m=
u
−v
=3
v=−3u
using equation (1)
−u×3u
u+3u
=
12
1
u=−16cm
∴v = 48 cm
So u−v= 64 cm
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1
Answer:
solution is in this pic
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