Question

Find the position of an object in a concave mirror when image is virtual and erect , and focal length is 15 cm , image is twice the object find object distance​

Answer 1

Answer:

This is a case where you know the magnification of the image, M = +2. The 2 is for twice the height and the plus sign comes from the fact that the image is upright. Real image magnifications are negative and inverted.

From the equation M = -(p/q) = 2, where p is object distance and q is image distance you can get a relationship between p and q. Solving for q gives:

q = -p/2

Using the equation 1/p + 1/q = 1/f and substituting gives

1/p + 1/(-p/2) = 1/f

This equation has only 1 unknown, the value of p, which is the answer to your question. If the algebra is done properly your answer will be less than the focal length f, which means you must place it somewhere between the focal point and the mirror.

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