Find the position of centre of mass of the uniform lamina shown in the figure. If small dish of radius a/2 is cut from disc of radius radius a.
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6
Answer:
Position of centre of mass = -a/6
Explainations:
Area of bigger circle = πa²
given radius of smaller circle = a/2
so,
area = πa²/4
next explaination refer to attachment
Answered by
63
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✌️✌️
✈
Area of bigger circle = πa²
given radius of smaller circle = a/2
so,
area = πa²/4.
✌️Thanks✌️
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