Question

Find the position of the image of an object placed at a distance of 12 cm from a convex mirror of focal length 10cm​

Answer 1

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In the given object distance u = - 12cm (by using sign convention). The focal length of the convex mirror, f = 10cm.

From mirror formula,

$\frac{1}{f} = \frac{1}{u} + \frac{1}{v } \: \: \: \frac{1}{10} = \frac{1}{ - 12} + \frac{1}{v}$

$therefore \: \frac{1}{v} = \frac{1}{10} + \frac{1}{12}$

$\frac{1}{v} = \frac{12 + 10}{120} \: \: \frac{1}{v} = \frac{120}{22} = 5.45$

The image distance is 5.45 cm.