Find the position size and nature of the image formed by a spherical mirror from the following data F=-12
U=-36
Ho=2cm
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Answer:
u=−20
f=−15
We know
f
1
=
v
1
+
u
1
−15
1
=
v
1
+
−20
1
v=−60cm
Now the magnification m=−
u
v
=−3
Height of object h=1cm
Height of image h
1
=∣m∣×h=3×1=3cm
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