FIND THE POSITION, SIZE AND THE NATURE OF THE IMAGE FORMED BY A SPHERICAL MIRROR FROM THE FOLLOWING DATA u=-20, f=-15, ho=1.0cm
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Given:
u= −20
f= −15
We know
f
1
=
v
1
+
u
1
−15
1
=
v
1
+
−20
1
v= −60cm
Now the magnification
m=
−
u
v
=
−3
Height of object
h=
1cm
Height of image
h
1
∣m∣×
h=
3×
1=
3cm
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