Question

find the positive integer n such that 1/10! + 1/11! +n^2/12! permutations and combinations ​

Answer 1

$ANSWER</p><p></p><p>Simplifying n−1C5+n−1C6<nC7</p><p></p><p>5!(n−6)!(n−1)!+6!(n−7)!(n−1)!=7!(n−7)!n!</p><p></p><p>6!(n−6)(n−7)!6(n−1)!+(n−6)(n−1)!=7!(n−7)!n!</p><p></p><p>6!(n−6)(n−7)!(n−1)!(6+n−6)=7!(n−7)!n!</p><p></p><p>n−61=71</p><p></p><p>n−6=7</p><p></p><p>n=13</p><p></p><p>Therefore, the value of n−7 is,</p><p></p><p>n−7=13−7</p><p></p><p>=6</p><p></p><p>$

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Answer 2

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