Math, asked by yoyodev, 10 months ago

find the positive integer whose cube exceeds its square by4624​

Answers

Answered by babugokulam3
3

Answer:

Step-by-step explanation:

Let no. be x

x^3-x^2=4624

By factorisation of 4624, we will get 17^3-17^2=4624

So the no. is 17

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