Question

Find the positive number which when increased by 8 will be equal to 128 times reciprocal of the original number

Answer 1

Answer:

8

Step-by-step explanation:

x + 8 = 1/x  * 128

x² + 8x = 128                                               (Multiplying both sides by x)

x² + 8x  - 128 = 0

x² + 16x - 8x - 128 = 0

x (x + 16) - 8 (x + 16) = 0

(x - 8)(x + 16) = 0

Therefore, (x - 8) = 0  ,    or  (x + 16) = 0

Therefore, x = 8,  or x = (-16)

Since x is positive, x = 8