Question

Find the positive root of 0.√3x^2-16 = 9.
Positive root of 0.root under 3x^2-16 = 9.

Answer 1

Answer:

Step-by-step explanation:

Hi ,

Sqrt ( 3x^2 + 6 ) = 9

Do the square bothsides of the

Equation.

3x^2 + 6 = 81

3x^2 = 81 - 6

3x^2 = 75

Divide bothsides with 3

3x^2 / 3 = 75/ 3

x^2 = 25

Now ,

x = sqrt ( 25 )

x = + or - 5

But we need pisitive root ,

therefore ,

x = 5

I hope this helps you.