Question

Find the positive root of √3

2 + 6 = 9.​

Answer 1

√3 equals to 1.4777

thanks for asking

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Answer 2

$\huge\bold\color{red}{\boxed{\boxed{☆Answer☆}}}$

$Consider, \: \: \: \sqrt{ ({3x})^{2} + 6 } = 9$

Squaring on both side :-

$= > {3x}^{2} + 6 = 81$

$= > {3x}^{2} = 81 - 6$

$= > {3x}^{2} = 75$

$= > {x}^{2} = \frac{75}{3}$

$= > {x}^{2} = 25$

$= > x = \sqrt{25}$

$= > x = ±5$

But positive root,

$= > \bold\color{green}{\boxed{ x = 5}}$