find the positive root of √3x^+6=9
suvarnaalapathi:
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root 3 x sq +6 = 9
root 3 x sq -3 = 0
root 3(x sq - root 3 ) = 0
x sq = root 3
x = root of root 3
root 3 x sq -3 = 0
root 3(x sq - root 3 ) = 0
x sq = root 3
x = root of root 3
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