find the positive root of √3x²+6=9
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Answered by
864
Hi ,
Sqrt ( 3x^2 + 6 ) = 9
Do the square bothsides of the
Equation.
3x^2 + 6 = 81
3x^2 = 81 - 6
3x^2 = 75
Divide bothsides with 3
3x^2 / 3 = 75/ 3
x^2 = 25
Now ,
x = sqrt ( 25 )
x = + or - 5
But we need pisitive root ,
therefore ,
x = 5
I hope this helps you.
****
Sqrt ( 3x^2 + 6 ) = 9
Do the square bothsides of the
Equation.
3x^2 + 6 = 81
3x^2 = 81 - 6
3x^2 = 75
Divide bothsides with 3
3x^2 / 3 = 75/ 3
x^2 = 25
Now ,
x = sqrt ( 25 )
x = + or - 5
But we need pisitive root ,
therefore ,
x = 5
I hope this helps you.
****
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412
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