Question

find the positive root of ✓3x²+6=9 ?​

Answer 1

Answer:

Hi ,

Hi ,Sqrt ( 3x^2 + 6 ) = 9

Hi ,Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of the

Hi ,Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of the Equation.

Hi ,Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of the Equation.3x^2 + 6 = 81

Hi ,Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of the Equation.3x^2 + 6 = 813x^2 = 81 - 6

Hi ,Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of the Equation.3x^2 + 6 = 813x^2 = 81 - 63x^2 = 75

Hi ,Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of the Equation.3x^2 + 6 = 813x^2 = 81 - 63x^2 = 75Divide bothsides with 3

Hi ,Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of the Equation.3x^2 + 6 = 813x^2 = 81 - 63x^2 = 75Divide bothsides with 33x^2 / 3 = 75/ 3

Hi ,Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of the Equation.3x^2 + 6 = 813x^2 = 81 - 63x^2 = 75Divide bothsides with 33x^2 / 3 = 75/ 3x^2 = 25

Hi ,Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of the Equation.3x^2 + 6 = 813x^2 = 81 - 63x^2 = 75Divide bothsides with 33x^2 / 3 = 75/ 3x^2 = 25Now ,

Hi ,Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of the Equation.3x^2 + 6 = 813x^2 = 81 - 63x^2 = 75Divide bothsides with 33x^2 / 3 = 75/ 3x^2 = 25Now ,x = sqrt ( 25 )

Hi ,Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of the Equation.3x^2 + 6 = 813x^2 = 81 - 63x^2 = 75Divide bothsides with 33x^2 / 3 = 75/ 3x^2 = 25Now ,x = sqrt ( 25 )x = + or - 5

Hi ,Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of the Equation.3x^2 + 6 = 813x^2 = 81 - 63x^2 = 75Divide bothsides with 33x^2 / 3 = 75/ 3x^2 = 25Now ,x = sqrt ( 25 )x = + or - 5But we need pisitive root ,

Hi ,Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of the Equation.3x^2 + 6 = 813x^2 = 81 - 63x^2 = 75Divide bothsides with 33x^2 / 3 = 75/ 3x^2 = 25Now ,x = sqrt ( 25 )x = + or - 5But we need pisitive root ,therefore ,

Hi ,Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of the Equation.3x^2 + 6 = 813x^2 = 81 - 63x^2 = 75Divide bothsides with 33x^2 / 3 = 75/ 3x^2 = 25Now ,x = sqrt ( 25 )x = + or - 5But we need pisitive root ,therefore ,x = 5

Hi ,Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of the Equation.3x^2 + 6 = 813x^2 = 81 - 63x^2 = 75Divide bothsides with 33x^2 / 3 = 75/ 3x^2 = 25Now ,x = sqrt ( 25 )x = + or - 5But we need pisitive root ,therefore ,x = 5I hope this helps you.

Hi ,Sqrt ( 3x^2 + 6 ) = 9Do the square bothsides of the Equation.3x^2 + 6 = 813x^2 = 81 - 63x^2 = 75Divide bothsides with 33x^2 / 3 = 75/ 3x^2 = 25Now ,x = sqrt ( 25 )x = + or - 5But we need pisitive root ,therefore ,x = 5I hope this helps you.****

Answer 2

Answer:

Genius

Hi ,

Sqrt ( 3x^2 + 6 ) = 9

Do the square bothsides of the

Equation.

3x^2 + 6 = 81

3x^2 = 81 - 6

3x^2 = 75

Divide bothsides with 3

3x^2 / 3 = 75/ 3

x^2 = 25

Now ,

x = sqrt ( 25 )

x = + or - 5

But we need pisitive root ,

therefore ,

x = 5

I hope this helps you.

****