Question

Find the positive root of /3x² + 6 = 9​

Answer 1

so,

$3x^{2} - 3= 0$

$3x^{2} = 3$

$x^{2} = 1$

$x = -1 or 1$

So, the positive root is

1

Answer 2

Answer:

Are you sure this is the question? 'cause we get an imaginary root as the solution.

$\sqrt{3} x^{2}$ = 9-6

$\sqrt{3} x^{2}$ = 3

$x^{2}$ = 3/$\sqrt{3}$

$x^{2}$ = $\sqrt{3}$

$x = \sqrt[4]{3}$

MARK ME AS BRAINLIEST!! GOOD LUCK :))