Find the positive root of
please solve the problem
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jatt62:
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3x ^2 +6 = ( 9 ) ^2
3x ^2 +6 = 81
3x ^2 = 81 - 6
3x ^2 = 75.
x^2 = 75 / 3
x ^2 = 2 5
x =
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x = + 5, - 5
For positive root, x = + 5.
3x ^2 +6 = 81
3x ^2 = 81 - 6
3x ^2 = 75.
x^2 = 75 / 3
x ^2 = 2 5
x =
x = + 5, - 5
For positive root, x = + 5.
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