Question

Find the positive root of quadratic equation
$\sqrt{3 } {x}^{2} + 6= 9$
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Answer 1

Answer:

$\sqrt{3} {x}^{2} + 6 = 9 \\ \sqrt{3} {x}^{2} = 9 - 6 \\ \sqrt{3} {x}^{2} = 3 \\ 3 {x}^{2} = {3}^{2} = 9 \\ 3x = \sqrt{9} = 3 \\ x = \frac{3}{3} \\ x = = 1$

X = 3/3

X=1