Question

Find the positive root of root[3x^2+6=9

Answer 1

Hi ,

Sqrt ( 3x^2 + 6 ) = 9

Do the square bothsides of the

Equation.

3x^2 + 6 = 81

3x^2 = 81 - 6

3x^2 = 75

Divide bothsides with 3

3x^2 / 3 = 75/ 3

x^2 = 25

Now ,

x = sqrt ( 25 )

x = + or - 5

But we need pisitive root ,

therefore ,

x = 5


Hope it helpful

Answer 2

Here is your answer
$\sqrt{3 {x}^{2} + 6} = 9 \\ 3 {x}^{2} + 6 = 9 {}^{2} \\ 3 {x}^{2} = 81 - 6 \\ 3 {x}^{2} = 75 \\ {x}^{2} = \frac{75}{3} \\ {x}^{2} = 25 \\ x = \sqrt{25} \\ x = 5 \: \: and \: - 5$
Therefore the positive root is 5

Hope it helps you