Question

find the positive root of square root of 3x square+6​=9

Answer 1

3x^2 + 6 = 9 can be changed into

3x^2 +6 -9 = 0

3x^2 - 3 = 0

square root of 3x^2 - 3 = 0 ,,will be

$(3 {x}^{2} - 3)(3 {x}^{2} - 3) = 0$

so,

$3 {x}^{2} - 3 = 0 \\ \\ 3 {x}^{2} = 3 \\ \\ {x}^{2} = 1 \\ \\ x = + 1 \: and \: - 1$

similarly roots of second factor will be +1 and -1

SO, THE POSITIVE ROOTS OF SQUARE ROOT OF

$3 {x}^{2} - 3 = 0$

are +1 AND +1.

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