Find the positive roots of root 3 x square + 6 is equals to 9
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3x^2+6= 9
3x^2= 9-6
3x^2= 3
x^2 = 3/3
x^2 = 1
x^2 = 1^2
x = 1 , -1
but the value of x is positive as mentioned in the question
hence,
x= 1
dia1140:
hi
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Hope thus helps you
√3x^2+6=9
Squaring both side
3x^2+6=81
3x^2=75
x^2=25
x=√25
x=5 or x=-5(Rejected as we have to find a positive factor)
Answer=5
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