Question

find the positive roots of
$\sqrt{3 {x}^{2} } + 6 = 9$
​

Answer 1

Step-by-step explanation:

$\sqrt{3 {x}^{2} } + 6 = 9$

bring 6 to RHS

$\sqrt{3 {x}^{2} } = 9 - 6 = 3$

SOBS

3x²=3

x=1

x= -1

but asked only positive root

so

x=1