Question

Find the positive square root of the following:
10+ 2√6 + √60 +2√10​

Answer 1

Answer:

Supposing you wanted to write 2√6, 2√10, 2√15, the square root would be (√2+√3+√5).

10+ 2√6+2√10+2√15

=10+2√2*√3+2√2*√5+2√3*√5

=(√2)^2+(√3)^2+(√5)^2+2√2*√3+2√2*√5+2√3*√5

Comparing with the form (a^2+b^2+c^2+2ab+2bc+2ca)=(a+b+c)^2

We get the square root as (√2+√3+√5)

Answer 2

$\bf\large\underline\pink{Solution:-}$

➤ Supposing you wanted to write 2√6, 2√10, 2√15, the square root would be (√2+√3+√5).

10+ 2√6+2√10+2√15

=10+2√2*√3+2√2*√5+2√3*√5

=(√2)^2+(√3)^2+(√5)^2+2√2*√3+2√2*√5+2√3*√5

Comparing with the form (a^2+b^2+c^2+2ab+2bc+2ca)=(a+b+c)^2

We get the square root as (√2+√3+√5).

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