Question

Find the positive value of k for which the equation kx2-6x-2=0 has real roots

Answer 1

kx2-6x-2=0
for real roots b2-4ac=0
(-6)2-4(k)(-2)=0
36+8k=0
8k=36
k=9/2
therefore the positive value of K is9/2
verification
b2-4ac
(-6)2-4(9/2)(-2)
-36+36
0
proved

Answer 2

Hey mate

Here is ur ans

So D=0

b^2-4ac=0

(6)^2-4(a)-2=0

36+8a=0

a=-36/8
a=-9/2

Verification


put the values in formula


b^2-4ac=0

36-4(-9/2)(-2)=0

36-36=0

0
_________'Hence proved____^_=

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