Find the positive value of k, for which the equation x^2+kx+64=0 and x^2-8x+k=0 will both have real roots?
Answers
Answered by
6
hope you find answer useful
Attachments:
achintayjoshioyfprm:
Thank you
Answered by
4
D≥0 for both.
We get, k²-4×64≥0 and 8²-4k≥0
k is in (-infinite,-16] U {16}
As k is positive, k=16 only
We get, k²-4×64≥0 and 8²-4k≥0
k is in (-infinite,-16] U {16}
As k is positive, k=16 only
are u crazy... bro verify your wrong answer with mine..lol
I did nit see that k is positive
not*
Similar questions
Geography,
8 months ago
Hindi,
8 months ago
Math,
1 year ago
Social Sciences,
1 year ago
Science,
1 year ago