Find the positive value of k, for which the equation x^2+kx+64=0 and x^2-8x+k=0 will both have real roots?
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D≥0 for both.
We get, k²-4×64≥0 and 8²-4k≥0
k is in (-infinite,-16] U {16}
As k is positive, k=16 only
We get, k²-4×64≥0 and 8²-4k≥0
k is in (-infinite,-16] U {16}
As k is positive, k=16 only
are u crazy... bro verify your wrong answer with mine..lol
I did nit see that k is positive
not*
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