Question

find the
positive value of k
which the
equation
x2+kx+64=0 and
x² - 8x+k =0 will both have real out​

Answer 1

Answer:

For x²-8x+k=0, D=(-8)²-4*1*k=64–4k. For real roots, 64–4k>=0, which is true for k<=16. So, the common point for k>=16 and k <=16 is only k=16. So, these 2 equations have real roots, only for k=16...

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