Question

find the positive value of the variable for which the given equation is satisfied


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Answer 1

★ Given :

$\frac{x^2 -9}{5+x^2} = \frac{5}{9}$

★ To find :

Value of x

★ Solution :

$\frac{x^2 -9}{5+x^2} = \frac{5}{9} \\ \\ \\ by \:cross\: multiplication \\ \\ \\ 9(x^2 -9) = 5(5+x^2) \\ \\ \\ 9x^2 - 81 =25 + 5x^2 \\ \\ \\ 9x^2 -5x^2 = 25+81 \\ \\ \\ 4x^2 = 106 \\ \\ \\ x^2 = \frac{106}{4} \\ \\ \\ x^2 = 26.5 \\ \\ \\ x = \sqrt{26.5} \\ \\ \\ {\pink{\boxed{x = 5.14 \:(approx)}}}$

Answer 2

NB:✔️means square root,x(2) x means raise to power.

Answer: 5.15

Explanation:

x(2)/5-9/x(2)=5/9

9(x(2)-9)=5(5+x(2))

9x(2)-5x(2)=25+81

4x(2)/4=106/4

✔️x(2)

✔️26.5

x=5.148

x=5.15

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