Question

Find the positive value of the variable for which the given equation is satisfied
1-x²÷1+x²= -4/5​

Answer 1

Answer:

$x=3$ satisfies the equation

Step-by-step explanation:

$\frac{1-x^{2} }{1+x^{2} } = \frac{-4}{5} \\\\ 1-x^{2} =\frac{-4}{5}(1+x^{2} ) \\1-x^{2} =\frac{-4}{5} -\frac{4x^{2} }{5} \\1+\frac{4}{5} =\frac{-4x^{2} }{5} +x^{2} \\\frac{5+4}{5}=\frac{-4x^{2} +5x^{2} }{5} \\9=x^{2} \\x=3$