Math, asked by divyang17, 11 months ago

find the positive value of x which satisfies the equation. x+5/2-x=-3/2​

Answers

Answered by rksinghdeo70
6

Hey mate..

Here's ur answer in the image.

Hope this helps u

Please mark it as branliest..

Attachments:

rksinghdeo70: No the answer is wrong.
rksinghdeo70: Answer is -4/5
divyang17: question me -3/2 hw
divyang17: he
rksinghdeo70: What's the answer??
rksinghdeo70: My answer is 16
rksinghdeo70: Is it correct??
divyang17: 4 h
divyang17: i cant open
rksinghdeo70: I had solved the problem with solution 4 please check it..
Answered by Anonymous
7

QUESTION :

find \: the \: positive \: value \: of \: x \: which \: satisfies \: the \: equation -  -  >  \frac{ {x}^{2 }  + 5}{2 -  {x}^{2} }  =  -  \times \frac{3}{2}

SOLUTION :

 =  > put {x}^{2}  = y \: in \: the \: given \: equation. \: then \: it \: becomes \\  \\  \\  \\  \\  \\  \\  \\   \frac{y + 5}{2 - y}  =  -  \times \frac{3}{2}

 by \: cross \: multiplication \: we \: get

 =  > 2(y + 5) =  - 3(2 - y)

 =  > 2y + 10 =  - 6 + 3y

 =  > 2y - 3y =  - 6 - 10

or

 =  >  - y =  - 16

 =  > y = 16

 =  > y =  {x}^{2}

 =  >  {x}^{2}  = 16 =  {4}^{2}

 =  > x = 4

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VERIFICATION: FOR X = 4

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l.h.s.  \frac{ {x}^{2 } + 5 }{2 -  {x}^{2} }  =   \frac{ {4}^{2}  + 5}{2 -  {4}^{2} }  =  \frac{16 + 5}{2 - 16}  =  \frac{21}{ - 14}  =  -  \times \frac{3}{2}  = r.h.s.

HENCE, X = 4

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