Question

find the positive value of y

y^2+4/3y^2=1/2​

Answer 1

Step-by-step explanation:

We have, (y2 + 4)/(3y2 + 7) = 1/2 By cross-multiplying we get, 2(y2 + 4) = 1(3y2 + 7) 2y2 + 8 = 3y2 + 7 3y2 – 2y2 = 7 – 8 y2 = -1 y = √-1 = 1

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