Question

find the positive values of k for which the quadratic
equcation x² - kx +9 = 0 has real and distinct
roots​

Answer 1

Answer:

k=6 or k=-6

Step-by-step explanation:

If the roots are equal(double root) it means that discriminant of quadratic equation

b^2-4ac=0

general form of quadratic equation is

ax^2+bx+c=0

in this case a=1 b=k and c=9

b^2-4ac=0 then:

k^2-36=0

(k-6)(k+6)=0

k=6 or k=-6

For k=6 or k= -6

given equation has real and equal roots

Answer 2

$\huge\underline\mathfrak\purple{Answer}$

$d = {b}^{2} - 4ac \\ \\ \: \: \: = {( - k)}^{2} - 4.1.9. \\ \\ \: \: \: = {k}^{2} - 36 \\ \\ \\ \\ \\ or \\ \\ \\ \\ {k}^{2} = 36. \\ \\ k = \sqrt{36}. \\ \\ k = 6 \: \: and \: \: - 6. \\ \\ \\ \\ your \: answer \: is \: 6.$

$<marquee>‼keep Smile ‼$

$<marquee>Mark as Brainlies$