Find the possible value of cosx, If cot x + cosecx = 5
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Answer:
Find the possible value of cos x , if cot x +cosec x= 5.
Easy
cotx+cosecx=5sinxcosx+sinx1=5cosx+1=5sinx
squaring both sides
(cosx+1)2=(5sinx)2cos2x+1+2cosx=25sin2xcos2x+1+2cosx=25(1−cos2x)26cos2x+2cosx−24=0
dividing by 2 we get
13cos2x+13cosx−12cosx−12=013cosx(cosx+1)−12(cosx+1)=0(13cosx−12)(cosx+1)cosx=1312orcosx=−1
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Step-by-step explanation:
cotx+cosecx=5
sinxcosx + sinx1=5
cosx+1=5sinx
squaring both sides
(cosx+1) 2=(5sinx) 2cos 2x+1+2cosx
=25sin 2 xcos 2
x+1+2cosx=25(1−cos 2x)26cos 2
x+2cosx−24=0
dividing by 2 we get
13cos 2 x+13cosx−12cosx−12=0
13cosx(cosx+1)−12(cosx+1)=0
(13cosx−12)(cosx+1)
cosx= 1312
or
cosx=−1
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