Question

Find the possible value of the constant k, if the roots of the quadratic equation x² – (k+ 2) x + 4 = 0

Answer 1

GIVEN:

• ${x}^{2} - (k + 2)x + 4 = 0$

ROOTS OF THE EQUATION WILL BE SAME WHEN b²=4ac

• ${(k + 2)}^{2} = 4 \times 1 \times 4 \\ = > {k}^{2} + 4k + 4 = 16 \\ = > {k}^{2} + 4k - 12 = 0 \\ \\ k1 = 2 \: \: \: \: \: \: \: \: k2 = - 6$

///MARK IT BRAINLIEST///