Find the possible value or values of z in the quadratic equation z2 – 4z + 4 = 0. A. z =√ 2 + 2, z = −√ 2 + 2 B. z = 10, z = 6 C. z = 2 D. z = 2√ 2 + 2, z = −√ 2 + 2
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Answer:
z=2
Step-by-step explanation:
z2 - 4z + 4=0
z2 - 2z - 2z + 4 = 0
z(z-2) -2(z-2)=0
(z-2) (z-2) = 0
z=0
hope it helps!!!
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