Question

Find the possible zeros of the polynomial :-
p(x) = 3x² + x + 2​

Answer 1

Answer:

2/3 and -1

Step-by-step explanation:

3x² + 3x - 2x + 2

3x (x + 1) - 2 (x + 1)

(3x - 2) (x + 1)

#1:

(3x - 2) = 0

3x = 2

x = 2/3

#2:

x + 1 = 0

x = -1