Question

find the potential at a distance of 18 cm from a charge 3 into 10 to the power minus 9 coulomb in a vacuum​

Answer 1

Answer:

Given : r=9 cm =0.09 m

Charge Q=3 nC =3×10

−9

C

Potential at a distance 9 cm, V=

r

kQ

where k=9×10

9

∴ V=

0.09

9×10

9

×3×10

−9

=300 V

Answer 2

Answer:

ANS : 300 V

Explanation:

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