Question

find the potential between two point p(1,-1,0) and q (2,1,3) with E=40xy I cape +20x square j cape + 2 f cape​

Answer 1

Answer:

n :

Given, E→=20x2iˆV/m

We know that : ∫dV=−∫E→.dr→ ⇒ ∫V2V1dV=−∫x2x120x2dx

∴ Potential difference, ΔV=20x∣x2x1 ⇒ V2−V1=20x2−20x1

(i) Potential difference between point A and B (ΔV for A to B)

VB−VA=2010−205=−2 volt

(ii) ΔV for x=∞ to x=5

V5−V∞=205−20∞ ∴ V5=10+4=14 volt

Step-by-step explanation:

otential difference between two point does not depend on reference value of potential. So, the potential difference between a and B does not depend on whether the potential at ∞ is 10 volt ot something else.