Question

find the potential difference across the 24 Ohm​

Answer 1

Answer:

$\frac{1}{12} \: A$

Voltage across each parallel resistance will be equal . Let that voltage be V .

Now equivalent resistance

$\frac{1}{r} = \frac{1}{48} + \frac{1}{48} + \frac{1}{24} + \frac{1}{6} + \frac{1}{4} + \frac{1}{2} \\ \\ \frac{1}{r} = \frac{1 + 1 + 2 + 8 + 12 + 24}{48} \\ \\ \frac{1}{r} = \frac{48}{48} = 1 \: \\ \\ r = 1$

So

V = Ir = 2 × 1 = 2V

For 24 ohm resistance , voltage across its end is 2V . So

I = V / r = 2 / 24 = 1/12 A