Find the potential difference between a and b if E=110 v and capacitance ratio c2 /c1=2
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Answer:
Given = refer the attached diagram
E= 110V
C1/C2 = 2
to find = potential difference
solution =
use the loop law in 2 closed loop,
110 - q2 /c + q1 - q2/ c = 0
-110 + q1 /2c + q1 - q2 / c = 0
q1 = (440C/3)
for potential difference ,
VN - Vm = q1 - q2 / C
= 110 /3volt
so,the potential difference between M and N or A and B is 110 /3volt
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