Question

Find the potential difference through which an electron be accelerated so that its de Broghe s wavelengtL becomes 0.1227 an ​

Answer 1

Answer:

• the potential difference through which an electron be accelerated so that its becomes.

Answer 2

Answer-The potential difference is 100v

Explanation-

Given - Broghe's wavelength $0.1227$

Find the potential difference

Solution-

The de-Broglie wavelength of an electron

$\lambda =\frac{\lambda}{\sqrt{2mev} }$

$0.1227=\frac{6.6\times 10^{-34}}{\sqrt{2(9.1\times^{-31})(1.6\times 10^{-19}\times v)} }$

${\sqrt{2(9.1\times^{-31})(1.6\times 10^{-19}\times v)} } =\frac{6.6\times 10^{-34}}{0.1227}$

$u=100volt$

Hence, the potential difference is 100v

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