Find the potential difference through which electron must be accelerated if we wish to resolve the diameter of virus 32 nm
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Answer:
The de-broglie wavelength of a particle with momentum p is λ=
p
h
⟹p=
λ
h
Hence the kinetic energy of the particle=
2m
p
2
=
2mλ
2
h
2
Hence the kinetic energy of the electron=
2m
e
eλ
e
2
h
2
eV
=150eV
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