Find the potential due to a charge of 3C at 1m away
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3
Answer:
Explanation:
V = k q / r
= 9*10^9 * 3 / 1
V = 27 * 10 ^9 V
Answered by
0
Explanation:
V=kQ/r where k=9×10^9
Q=3C & r=1m
putting the values in the formula
V=9×10^9×3/1=2.7×10^10 volts
finally we get, potential at 1m away from 3C charge is 2.7×10^10 volts
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