Find the potential energy of a body of mass 50 kg. If it is lifted to a height of 3m. Now this body is allowed to fall freely, then find the kinetic energy of the body when it is exactly half way. (g = 10m/s²)
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Given:-
m=50kg , it's lifted up so we got height (h)=3m,g=10m/s²
We know that potential energy (u)=mgh
U= 50×10×3
U= 1500j
We also know that when the object is held half way down it's potential energy becomes kinetic energy/2.
i.e. potential energy of the object=kinetic energy/2
Therefore now we can substitute the values to the equation given above to get the value of kinetic energy of the body.
U=1500/2=750J
Hence, kinetic energy at that moment becomes 750J.
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