Question

Find the potential energy of a system of four particles placed at the vertices square of side 'a' .Also obtain the potential at the center of the square??? Please help me ╥﹏╥.... no ❌google xD.. .. class 11 Physics question​

Answer 1

Explanation:

The system can be made by bringing each charge from reference (∞) and  

placing them on  the vertices of the square

Then net work  done in arranging the system = Potentital energy of teh system 

For  bringing 1st  charge : W1=0

For bringing 2nd charge : W2l2kqq (assuming each charge = q and side = l)

For bringing 3rd charge : W3=l2kqq+(2l)2kqq

For bringing 4th charge: W4=l2kqq+l2kqq+(2l)2kqq

Hence total work done = W1+W2+W3+W4=l25kq2 i.e. potential energy of system 

The  potential at centra = 4×(21)2kq=i

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