find the potential energy of the system of four particles each of mass M placed at the vertices of a square of side l and also obtain the potential energy at the centre of the square
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Answer: Let A, B, C, D be the 4 point objects at the corner of a square of side l.
Then total potential energy of the system
= -[GMaMb/l + GMaMc/(l√2) + GMaMd/l]
{Ma=Mb=Mc=M}
=-[GM^2/l + GM^2/l√2 + GM^2/l]
=-[GM^2/l][2+√2}
Explanation:
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