Question

Find the power dissipated in the 27 ohm resistor, ifthe potential difference across 4ohm resistor is20 V.(1) 59 W(2) 96 W(3) 108 W(4) 121 W​

Answer 1

Given,

• Potential Difference(V) = 20 V

• Resistance (R) = 4 Ω

$\boxed{\displaystyle\sf{Current\:(I)=\frac{Potential\:Difference\:(V)}{Resistance\:(R)}}}$

Applying the values to the equation,

$\implies\displaystyle\sf{I=\frac{20}{4}}$

$\implies\displaystyle\sf{I=5\:A}$

We have to find the power.

$\boxed{\displaystyle\sf{Power\:(P)=I^2\times R}}$

$\implies\displaystyle\sf{P=(5)^2\times27}$

$\implies\displaystyle\sf{P=25\times27}$

$\implies\displaystyle\sf{P=675\:W}$

$\boxed{\displaystyle\sf{Power=675\:W}}$