Find the power of a lens of focal length 0.20m.
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Answered by
1
Answer:
Given f1=0.20m,f2=0.30m. ∴f=0.12m. Power of the first lens P1=1f1=10.20=5D. Power of the second lens P2=1f2=10.30=3.333D.
Explanation:
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Answered by
0
Answer:
F1=0.20m, f2=0.30m.
f=0.12m. power of the first lens p1=1f1=10.20.=5D .
power of the second lens
Explanation:
p2=1 f2=10.30=333D.
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