Question

find the power of an engine which can do a work of 1200j in 8 second​

Answer 1

Answer:

2009p is the second ppower of an engine which can do

Answer 2

Explanation:

Power = Joule/Second

Given,

Joule= 1200j

Second = 8 seconds

So,

Power = 1200/8

That is equal to 140watt